JEE Math Practice Question
Let $C: x^2+y^2=4$ and $C^{\prime}: x^2+y^2-4 \lambda x+9=0$ be two circles. If the set of all values of $\lambda$ so that the circles $\mathrm{C}$ and $\mathrm{C}$ intersect at two distinct points, is $\mathrm{R}-[\mathrm{a}, \mathrm{b}]$, then the point $(8 \mathrm{a}+12,16 \mathrm{~b}-20)$ lies on the curve :
- A.$x^2+2 y^2-5 x+6 y=3$
- B.$5 x^2-y=-11$
- C.$x^2-4 y^2=7$
- D.$6 x^2+y^2=42$
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