JEE Math Practice Question
The locus of the mid points of the chords of the circle $${C_1}:{(x - 4)^2} + {(y - 5)^2} = 4$$ which subtend an angle $${\theta _i}$$ at the centre of the circle $$C_1$$, is a circle of radius $$r_i$$. If $${\theta _1} = {\pi \over 3},{\theta _3} = {{2\pi } \over 3}$$ and $$r_1^2 = r_2^2 + r_3^2$$, then $${\theta _2}$$ is equal to :
- A.$${\pi \over 2}$$
- B.$${\pi \over 4}$$
- C.$${{3\pi } \over 4}$$
- D.$${\pi \over 6}$$
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