JEE Math Practice Question
The points of intersection of the line $$ax + by = 0,(a \ne b)$$ and the circle $${x^2} + {y^2} - 2x = 0$$ are $$A(\alpha ,0)$$ and $$B(1,\beta )$$. The image of the circle with AB as a diameter in the line $$x + y + 2 = 0$$ is :
- A.$${x^2} + {y^2} + 5x + 5y + 12 = 0$$
- B.$${x^2} + {y^2} + 3x + 5y + 8 = 0$$
- C.$${x^2} + {y^2} - 5x - 5y + 12 = 0$$
- D.$${x^2} + {y^2} + 3x + 3y + 4 = 0$$
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