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JEE Math Practice Question

Let the tangents at the points $$A(4,-11)$$ and $$B(8,-5)$$ on the circle $$x^{2}+y^{2}-3 x+10 y-15=0$$, intersect at the point $$C$$. Then the radius of the circle, whose centre is $$C$$ and the line joining $$A$$ and $$B$$ is its tangent, is equal to :

  1. A.$$\frac{2\sqrt{13}}{3}$$
  2. B.$$\frac{3\sqrt{3}}{4}$$
  3. C.$$\sqrt{13}$$
  4. D.$$2\sqrt{13}$$

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