JEE Math Practice Question
Let $$y=x+2,4y=3x+6$$ and $$3y=4x+1$$ be three tangent lines to the circle $$(x-h)^2+(y-k)^2=r^2$$. Then $$h+k$$ is equal to :
- A.6
- B.5 (1 + $$\sqrt2$$)
- C.5
- D.5$$\sqrt2$$
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