JEE Math Practice Question
Let a circle C touch the lines $${L_1}:4x - 3y + {K_1} = 0$$ and $${L_2} = 4x - 3y + {K_2} = 0$$, $${K_1},{K_2} \in R$$. If a line passing through the centre of the circle C intersects L1 at $$( - 1,2)$$ and L2 at $$(3, - 6)$$, then the equation of the circle C is :
- A.$${(x - 1)^2} + {(y - 2)^2} = 4$$
- B.$${(x + 1)^2} + {(y - 2)^2} = 4$$
- C.$${(x - 1)^2} + {(y + 2)^2} = 16$$
- D.$${(x - 1)^2} + {(y - 2)^2} = 16$$
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