JEE Math Practice Question
If the tangents drawn at the points $$O(0,0)$$ and $$P\left( {1 + \sqrt 5 ,2} \right)$$ on the circle $${x^2} + {y^2} - 2x - 4y = 0$$ intersect at the point Q, then the area of the triangle OPQ is equal to :
- A.$${{3 + \sqrt 5 } \over 2}$$
- B.$${{4 + 2\sqrt 5 } \over 2}$$
- C.$${{5 + 3\sqrt 5 } \over 2}$$
- D.$${{7 + 3\sqrt 5 } \over 2}$$
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