JEE Math Practice Question
If a circle of radius R passes through the origin O and intersects the coordinates axes at A and B, then the locus of the foot of perpendicular from O on AB is :
- A.(x2 + y2)2 = 4R2x2y2
- B.(x2 + y2) (x + y) = R2xy
- C.(x2 + y2)2 = 4Rx2y2
- D.(x2 + y2)3 = 4R2x2y2
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