JEE Math Practice Question
The radius of a circle, having minimum area, which touches the curve y = 4 – x2 and the lines, y = |x| is :
- A.$$2\left( {\sqrt 2 - 1} \right)$$
- B.$$4\left( {\sqrt 2 - 1} \right)$$
- C.$$4\left( {\sqrt 2 + 1} \right)$$
- D.$$2\left( {\sqrt 2 + 1} \right)$$
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