JEE Math Practice Question
If one of the diameters of the circle, given by the equation, $${x^2} + {y^2} - 4x + 6y - 12 = 0,$$ is a chord of a circle $$S$$, whose centre is at $$(-3, 2)$$, then the radius of $$S$$ is :
- A.$$5$$
- B.$$10$$
- C.$$5\sqrt 2 $$
- D.$$5\sqrt 3 $$
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