JEE Math Practice Question
Three distinct points A, B and C are given in the 2 -dimensional coordinates plane such that the ratio of the distance of any one of them from the point $$(1, 0)$$ to the distance from the point $$(-1, 0)$$ is equal to $${1 \over 3}$$. Then the circumcentre of the triangle ABC is at the point :
- A.$$\left( {{5 \over 4},0} \right)$$
- B.$$\left( {{5 \over 2},0} \right)$$
- C.$$\left( {{5 \over 3},0} \right)$$
- D.$$\left( {0,0} \right)$$
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