JEE Math Practice Question
If the lines $$3x - 4y - 7 = 0$$ and $$2x - 3y - 5 = 0$$ are two diameters of a circle of area $$49\pi $$ square units, the equation of the circle is :
- A.$$\,{x^2} + {y^2} + 2x\, - 2y - 47 = 0\,$$
- B.$$\,{x^2} + {y^2} + 2x\, - 2y - 62 = 0\,$$
- C.$${x^2} + {y^2} - 2x\, + 2y - 62 = 0$$
- D.$${x^2} + {y^2} - 2x\, + 2y - 47 = 0$$
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