JEE Math Practice Question

If the pair of lines $$a{x^2} + 2\left( {a + b} \right)xy + b{y^2} = 0$$ lie along diameters of a circle and divide the circle into four sectors such that the area of one of the sectors is thrice the area of another sector then :

1. A.$$3{a^2} - 10ab + 3{b^2} = 0$$
2. B.$$3{a^2} - 2ab + 3{b^2} = 0$$
3. C.$$3{a^2} + 10ab + 3{b^2} = 0$$
4. D.$$3{a^2} + 2ab + 3{b^2} = 0$$