JEE Math Practice Question
Let $\left|\frac{\bar{z}-i}{2 \bar{z}+i}\right|=\frac{1}{3}, z \in C$, be the equation of a circle with center at $C$. If the area of the triangle, whose vertices are at the points $(0,0), C$ and $(\alpha, 0)$ is 11 square units, then $\alpha^2$ equals:
- A.$\frac{121}{25}$
- B.100
- C.$\frac{81}{25}$
- D.50
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