JEE Math Practice Question
Let the curve $z(1+i)+\bar{z}(1-i)=4, z \in C$, divide the region $|z-3| \leq 1$ into two parts of areas $\alpha$ and $\beta$. Then $|\alpha-\beta|$ equals :
- A.$1+\frac{\pi}{3}$
- B.$1+\frac{\pi}{6}$
- C.$1+\frac{\pi}{2}$
- D.$1+\frac{\pi}{4}$
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