JEE Math Practice Question
Let $$z$$ be a complex number such that $$|z+2|=1$$ and $$\operatorname{lm}\left(\frac{z+1}{z+2}\right)=\frac{1}{5}$$. Then the value of $$|\operatorname{Re}(\overline{z+2})|$$ is
- A.$$\frac{2 \sqrt{6}}{5}$$
- B.$$\frac{24}{5}$$
- C.$$\frac{\sqrt{6}}{5}$$
- D.$$\frac{1+\sqrt{6}}{5}$$
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