JEE Math Practice Question
Let $$S=\left\{z \in \mathbb{C}: \bar{z}=i\left(z^{2}+\operatorname{Re}(\bar{z})\right)\right\}$$. Then $$\sum\limits_{z \in \mathrm{S}}|z|^{2}$$ is equal to :
- A.$$\frac{7}{2}$$
- B.4
- C.3
- D.$$\frac{5}{2}$$
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