JEE Math Practice Question
If $${\left( {\sqrt 3 + i} \right)^{100}} = {2^{99}}(p + iq)$$, then p and q are roots of the equation :
- A.$${x^2} - \left( {\sqrt 3 - 1} \right)x - \sqrt 3 = 0$$
- B.$${x^2} + \left( {\sqrt 3 + 1} \right)x + \sqrt 3 = 0$$
- C.$${x^2} + \left( {\sqrt 3 - 1} \right)x - \sqrt 3 = 0$$
- D.$${x^2} - \left( {\sqrt 3 + 1} \right)x + \sqrt 3 = 0$$
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