JEE Math Practice Question
The value of $${\left( {{{1 + \sin {{2\pi } \over 9} + i\cos {{2\pi } \over 9}} \over {1 + \sin {{2\pi } \over 9} - i\cos {{2\pi } \over 9}}}} \right)^3}$$ is :
- A.$${1 \over 2}\left( {\sqrt 3 - i} \right)$$
- B.-$${1 \over 2}\left( {\sqrt 3 - i} \right)$$
- C.$$ - {1 \over 2}\left( {1 - i\sqrt 3 } \right)$$
- D.$${1 \over 2}\left( {1 - i\sqrt 3 } \right)$$
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