JEE Math Practice Question
If the cube roots of unity are 1, $$\omega \,,\,{\omega ^2}$$ then the roots of the equation $${(x - 1)^3}$$ + 8 = 0, are :
- A.$$ - 1, - 1 + 2\,\,\omega , - 1 - 2\,\,{\omega ^2}$$
- B.$$ - 1, - 1, - 1$$
- C.$$ - 1,1 - 2\omega ,1 - 2{\omega ^2}$$
- D.$$ - 1,1 + 2\omega ,1 + 2{\omega ^2}$$
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