JEE Math Practice Question
The integral $\int_0^\pi \frac{(x+3) \sin x}{1+3 \cos ^2 x} d x$ is equal to
- A.$\frac{\pi}{\sqrt{3}}(\pi+1)$
- B.$\frac{\pi}{3 \sqrt{3}}(\pi+6)$
- C.$\frac{\pi}{\sqrt{3}}(\pi+2)$
- D.$\frac{\pi}{2 \sqrt{3}}(\pi+4)$
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