JEE Math Practice Question
If the value of the integral $$\int\limits_{-1}^1 \frac{\cos \alpha x}{1+3^x} d x$$ is $$\frac{2}{\pi}$$.Then, a value of $$\alpha$$ is
- A.$$\frac{\pi}{2}$$
- B.$$\frac{\pi}{4}$$
- C.$$\frac{\pi}{3}$$
- D.$$\frac{\pi}{6}$$
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