JEE Math Practice Question
Let $$5 f(x)+4 f\left(\frac{1}{x}\right)=\frac{1}{x}+3, x > 0$$. Then $$18 \int\limits_{1}^{2} f(x) d x$$ is equal to :
- A.$$10 \log _{\mathrm{e}} 2+6$$
- B.$$5 \log _{e} 2-3$$
- C.$$10 \log _{\mathrm{e}} 2-6$$
- D.$$5 \log _{\mathrm{e}} 2+3$$
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