JEE Math Practice Question
$$\int\limits_{{{3\sqrt 2 } \over 4}}^{{{3\sqrt 3 } \over 4}} {{{48} \over {\sqrt {9 - 4{x^2}} }}dx} $$ is equal to :
- A.$${\pi \over 2}$$
- B.$${\pi \over 3}$$
- C.$${\pi \over 6}$$
- D.$$2\pi $$
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