JEE Math Practice Question
Let $\alpha>0$. If $\int\limits_0^\alpha \frac{x}{\sqrt{x+\alpha}-\sqrt{x}} \mathrm{~d} x=\frac{16+20 \sqrt{2}}{15}$, then $\alpha$ is equal to :
- A.4
- B.2
- C.$2 \sqrt{2}$
- D.$\sqrt{2}$
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