JEE Math Practice Question
If $$f(\alpha)=\int\limits_{1}^{\alpha} \frac{\log _{10} \mathrm{t}}{1+\mathrm{t}} \mathrm{dt}, \alpha>0$$, then $$f\left(\mathrm{e}^{3}\right)+f\left(\mathrm{e}^{-3}\right)$$ is equal to :
- A.9
- B.$$\frac{9}{2}$$
- C.$$\frac{9}{\log _{e}(10)}$$
- D.$$\frac{9}{2 \log _{e}(10)}$$
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