JEE Math Practice Question
The value of $$\int\limits_{{{ - 1} \over {\sqrt 2 }}}^{{1 \over {\sqrt 2 }}} {{{\left( {{{\left( {{{x + 1} \over {x - 1}}} \right)}^2} + {{\left( {{{x - 1} \over {x + 1}}} \right)}^2} - 2} \right)}^{{1 \over 2}}}dx} $$ is :
- A.loge 4
- B.loge 16
- C.2loge 16
- D.4loge (3 + 2$${\sqrt 2 }$$)
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