JEE Math Practice Question
The value of the integral $$\int\limits_{ - 1}^1 {{{\log }_e}(\sqrt {1 - x} + \sqrt {1 + x} )dx} $$ is equal to:
- A.$${1 \over 2}{\log _e}2 + {\pi \over 4} - {3 \over 2}$$
- B.$$2{\log _e}2 + {\pi \over 4} - 1$$
- C.$${\log _e}2 + {\pi \over 2} - 1$$
- D.$$2{\log _e}2 + {\pi \over 2} - {1 \over 2}$$
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