JEE Math Practice Question
Consider the integral $$I = \int_0^{10} {{{[x]{e^{[x]}}} \over {{e^{x - 1}}}}dx} $$, where [x] denotes the greatest integer less than or equal to x. Then the value of I is equal to :
- A.45 (e $$-$$ 1)
- B.45 (e + 1)
- C.9 (e + 1)
- D.9 (e $$-$$ 1)
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