JEE Math Practice Question
For x > 0, if $$f(x) = \int\limits_1^x {{{{{\log }_e}t} \over {(1 + t)}}dt} $$, then $$f(e) + f\left( {{1 \over e}} \right)$$ is equal to :
- A.$${1 \over 2}$$
- B.$$-$$1
- C.0
- D.1
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