JEE Math Practice Question
$$\mathop {\lim }\limits_{x \to 0} {{\int\limits_0^{{x^2}} {\left( {\sin \sqrt t } \right)dt} } \over {{x^3}}}$$ is equal to :
- A.$${1 \over {15}}$$
- B.0
- C.$${2 \over 3}$$
- D.$${3 \over 2}$$
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