JEE Math Practice Question

If $$I = \int\limits_1^2 {{{dx} \over {\sqrt {2{x^3} - 9{x^2} + 12x + 4} }}} $$, then :

1. A.$${1 \over 16} < {I^2} < {1 \over 9}$$
2. B.$${1 \over 8} < {I^2} < {1 \over 4}$$
3. C.$${1 \over 9} < {I^2} < {1 \over 8}$$
4. D.$${1 \over 6} < {I^2} < {1 \over 2}$$