JEE Math Practice Question
If $$\int\limits_0^{{\pi \over 3}} {{{\tan \theta } \over {\sqrt {2k\,\sec \theta } }}} \,d\theta = 1 - {1 \over {\sqrt 2 }},\left( {k > 0} \right),$$ then value of k is :
- A.4
- B.$${1 \over 2}$$
- C.1
- D.2
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