JEE Math Practice Question
A value of $$\alpha $$ such that $$\int\limits_\alpha ^{\alpha + 1} {{{dx} \over {\left( {x + \alpha } \right)\left( {x + \alpha + 1} \right)}}} = {\log _e}\left( {{9 \over 8}} \right)$$ is :
- A.2
- B.- 2
- C.$${1 \over 2}$$
- D.$$-{1 \over 2}$$
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