JEE Math Practice Question
If $$2\int\limits_0^1 {{{\tan }^{ - 1}}xdx = \int\limits_0^1 {{{\cot }^{ - 1}}} } \left( {1 - x + {x^2}} \right)dx,$$ then $$\int\limits_0^1 {{{\tan }^{ - 1}}} \left( {1 - x + {x^2}} \right)dx$$ is equalto :
- A.log4
- B.$${\pi \over 2}$$ + log2
- C.log2
- D.$${\pi \over 2}$$ $$-$$ log4
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