JEE Math Practice Question
$$\mathop {\lim }\limits_{n \to \infty } {\left( {{{\left( {n + 1} \right)\left( {n + 2} \right)...3n} \over {{n^{2n}}}}} \right)^{{1 \over n}}}$$ is equal to:
- A.$${9 \over {{e^2}}}$$
- B.$$3\,\log \,3 - 2$$
- C.$${{18} \over {{e^4}}}$$
- D.$${{27} \over {{e^2}}}$$
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