JEE Math Practice Question
The integral $$\int\limits_2^4 {{{\log \,{x^2}} \over {\log {x^2} + \log \left( {36 - 12x + {x^2}} \right)}}dx} $$ is equal to :
- A.$$1$$
- B.$$6$$
- C.$$2$$
- D.$$4$$
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