JEE Math Practice Question
If $$\int\limits_0^\pi {xf\left( {\sin x} \right)dx = A\int\limits_0^{\pi /2} {f\left( {\sin x} \right)dx,} } $$ then $$A$$ is
- A.$$2\pi $$
- B.$$\pi $$
- C.$${\pi \over 4}$$
- D.$$0$$
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