JEE Math Practice Question
If $$y=f(x)$$ makes +$$ve$$ intercept of $$2$$ and $$0$$ unit on $$x$$ and $$y$$ axes and encloses an area of $$3/4$$ square unit with the axes then $$\int\limits_0^2 {xf'\left( x \right)dx} $$ is
- A.$$3/2$$
- B.$$1$$
- C.$$5/4$$
- D.$$-3/4$$
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