JEE Math Practice Question
$$\int_{ - \pi }^\pi {{{2x\left( {1 + \sin x} \right)} \over {1 + {{\cos }^2}x}}} dx$$ is
- A.$${{{\pi ^2}} \over 4}$$
- B.$${{\pi ^2}}$$
- C.zero
- D.$${\pi \over 2}$$
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