JEE Math Practice Question
Let the shortest distance from $(a, 0), a>0$, to the parabola $y^2=4 x$ be 4 . Then the equation of the circle passing through the point $(a, 0)$ and the focus of the parabola, and having its centre on the axis of the parabola is :
- A.$x^2+y^2-8 x+7=0$
- B.$x^2+y^2-6 x+5=0$
- C.$x^2+y^2-4 x+3=0$
- D.$x^2+y^2-10 x+9=0$
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