JEE Math Practice Question
Let P be a point on the parabola, y2 = 12x and N be the foot of the perpendicular drawn from P on the axis of the parabola. A line is now drawn through the mid-point M of PN, parallel to its axis which meets the parabola at Q. If the y-intercept of the line NQ is $${4 \over 3}$$, then :
- A.MQ = $${1 \over 3}$$
- B.PN = 4
- C.PN = 3
- D.MQ = $${1 \over 4}$$
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