JEE Math Practice Question
Equation of a common tangent to the circle, x2 + y2 – 6x = 0 and the parabola, y2 = 4x is :
- A.$$2\sqrt 3 $$y = 12x + 1
- B.$$\sqrt 3 $$y = x + 3
- C.$$2\sqrt 3 $$y = -x - 12
- D.$$\sqrt 3 $$y = 3x + 1
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