JEE Math Practice Question

Let $$P$$ be the point on the parabola, $${{y^2} = 8x}$$ which is at a minimum distance from the centre $$C$$ of the circle, $${x^2} + {\left( {y + 6} \right)^2} = 1$$. Then the equation of the circle, passing through $$C$$ and having its centre at $$P$$ is:

1. A.$${{x^2} + {y^2} - {x \over 4} + 2y - 24 = 0}$$
2. B.$${{x^2} + {y^2} - 4x + 9y + 18 = 0}$$
3. C.$${{x^2} + {y^2} - 4x + 8y + 12 = 0}$$
4. D.$${{x^2} + {y^2} - x + 4y - 12 = 0}$$