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JEE Math Practice Question

$$ \text { Let } f(x)=a x^{2}+b x+c \text { be such that } f(1)=3, f(-2)=\lambda \text { and } $$ $$f(3)=4$$. If $$f(0)+f(1)+f(-2)+f(3)=14$$, then $$\lambda$$ is equal to :

  1. A.$$-$$4
  2. B.$$\frac{13}{2}$$
  3. C.$$\frac{23}{2}$$
  4. D.4

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