JEE Math Practice Question
If $$f(x) = {\log _e}\left( {{{1 - x} \over {1 + x}}} \right)$$, $$\left| x \right| < 1$$ then $$f\left( {{{2x} \over {1 + {x^2}}}} \right)$$ is equal to
- A.2f(x2)
- B.2f(x)
- C.(f(x))2
- D.-2f(x)
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