JEE Math Practice Question
Let f : A $$ \to $$ B be a function defined as f(x) = $${{x - 1} \over {x - 2}},$$ Where A = R $$-$$ {2} and B = R $$-$$ {1}. Then f is :
- A.invertible and $${f^{ - 1}}(y) = $$ $${{3y - 1} \over {y - 1}}$$
- B.invertible and $${f^{ - 1}}\left( y \right) = {{2y - 1} \over {y - 1}}$$
- C.invertible and $${f^{ - 1}}\left( y \right) = {{2y + 1} \over {y - 1}}$$
- D.not invertible
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