JEE Math Practice Question
Let $$f\left( x \right) = {\left( {x + 1} \right)^2} - 1,x \ge - 1$$ Statement - 1 : The set $$\left\{ {x:f\left( x \right) = {f^{ - 1}}\left( x \right)} \right\} = \left\{ {0, - 1} \right\}$$. Statement - 2 : $$f$$ is a bijection.
- A.Statement - 1 is true, Statement - 2 is true; Statement - 2 is a correct explanation for Statement - 1
- B.Statement - 1 is true, Statement - 2 is true; Statement - 2 is not a correct explanation for Statement - 1
- C.Statement - 1 is true, Statement - 2 is false
- D.Statement - 1 is false, Statement - 2 is true
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