JEE Math Practice Question
Let $$f:( - 1,1) \to B$$, be a function defined by $$f\left( x \right) = {\tan ^{ - 1}}{{2x} \over {1 - {x^2}}}$$, then $$f$$ is both one-one and onto when B is the interval
- A.$$\left( {0,{\pi \over 2}} \right)$$
- B.$$\left[ {0,{\pi \over 2}} \right)$$
- C.$$\left[ { - {\pi \over 2},{\pi \over 2}} \right]$$
- D.$$\left( { - {\pi \over 2},{\pi \over 2}} \right)$$
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