JEE Math Practice Question
If $$\int \frac{1}{\mathrm{a}^2 \sin ^2 x+\mathrm{b}^2 \cos ^2 x} \mathrm{~d} x=\frac{1}{12} \tan ^{-1}(3 \tan x)+$$ constant, then the maximum value of $$\mathrm{a} \sin x+\mathrm{b} \cos x$$, is :
- A.$$\sqrt{41}$$
- B.$$\sqrt{39}$$
- C.$$\sqrt{40}$$
- D.$$\sqrt{42}$$
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